9.1.7 Checkerboard V2 Answers Patched -

For more practice on similar grid-based logic, you can explore the CodeHS Python Curriculum which covers 2D lists and nested iterations in detail.

To solve this, you first initialize an 8x8 grid of zeros. Then, use a nested loop to check if the sum of the row index and column index is odd or even to determine where to place the 1 s. 9.1.7 checkerboard v2 answers

: Ensure your loops run exactly range(8) to match the 8x8 requirement. For more practice on similar grid-based logic, you

# Function to print the board in a readable format def print_board(board): for row in board: print(" ".join([str(x) for x in row])) # 1. Initialize an 8x8 grid filled with 0s board = [] for i in range(8): board.append([0] * 8) # 2. Use nested loops to apply the checkerboard pattern for row in range(8): for col in range(8): # If the sum of row + col is odd, set the value to 1 # This creates the alternating pattern if (row + col) % 2 != 0: board[row][col] = 1 # 3. Output the result print_board(board) Use code with caution. Why This Works : Ensure your loops run exactly range(8) to

: In Python, improper indentation of your nested loops will cause a SyntaxError or logic failure. Ensure your if statement is inside the second loop.

This ensures that no two adjacent squares (horizontal or vertical) have the same value. Common Pitfalls